Hello
Problem :
i(t) = 10 sin(200 pi t)
Find q between t=0 s and t=0.01s
I know that it is a straightforward problem.
q=integration of i(t) from t=0 to t=0.01
The problem here is that the value of the integral equal zero!
q = 10 integration of ( sin(200 pi t) ) from t=0 to t=0.01
= ( - 10 / 200 pi ) [ cos(200 pi t) ] from t=0 to t=0.01
= ( -1 / 20 pi) [ cos( (200) (0.01) pi ) - cos(0) ]
Now the big problem is what is pi ?!!
is it 3.14 or 180 ?
Our T.A. said that if your calculator is in degrees, then pi=180
and if it is in radians, then pi = 3.14
My calculator is in degree, so i will put pi = 180
but this give me zero !
Any help?
Problem :
i(t) = 10 sin(200 pi t)
Find q between t=0 s and t=0.01s
I know that it is a straightforward problem.
q=integration of i(t) from t=0 to t=0.01
The problem here is that the value of the integral equal zero!
q = 10 integration of ( sin(200 pi t) ) from t=0 to t=0.01
= ( - 10 / 200 pi ) [ cos(200 pi t) ] from t=0 to t=0.01
= ( -1 / 20 pi) [ cos( (200) (0.01) pi ) - cos(0) ]
Now the big problem is what is pi ?!!
is it 3.14 or 180 ?
Our T.A. said that if your calculator is in degrees, then pi=180
and if it is in radians, then pi = 3.14
My calculator is in degree, so i will put pi = 180
but this give me zero !
Any help?