I am simulating it in Multisim. No, there is no light falling on the LED even in the simulation. ( I believe you were trying to tell me that there is some voltage going in reverse from an extraneous light source shining down on the LED).hi Nathan,
I am assuming you are using an actual circuit, not a simulation.???
Is there a strong light falling on the LED.??
Try covering it with your hand.
E
Could you please retype part 2 of your answer? I dont understand it well. Thank you1. LED1 has capacitance and some voltage presents after S1 is OFF.
2. You need to place S1 in +wire, because now S1 serarates ground from right part of circuit.
It may affects on simulation accuracy.
I think you are correct. The switch did have a resistance of 100M ohms. I changed it to 1000000000M ohms and the voltage is now 2.4 milli volts across the LED. Thanks!Your program can produce such an amazing result for two reasons. The first reason may not be the ideal switch element. When switched off, the resistance may not be infinite (usually in simulators).
The second reason may be that the simulator has a conductivity (albeit very low) from each node to the ground.
If you remove one connection to the LED, it should read 0V.I think you are correct. The switch did have a resistance of 100M ohms. I changed it to 1000000000M ohms and the voltage is now 2.4 milli volts across the LED. Thanks!
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