Hi,

from so many days am not clear at full wave bridge rectifier calculation.
consider i have used 8-0-8 step up trnasformer and bridge rectifeir is designed.
what will be the voltage at transformer secondery and volatge at bridge rectifier output.
requesting you to help me with clear gud example of full wave bridge rectifier with calculations.

Thank you
Sarika

 

Hello sarika rajesh

In these cases it is much faster query in Google.com
I found this: http://www.electronics-tutorials.ws/diode/diode_6.html


I guess that will serve Your purposes

 

AC 8-0-8 → Full wave rectifier → Cap filter → Vout
Vout = 8Vac x 1.414 - (0.7V*2) = 11.3Vdc - 1.4Vdc =9.9Vdc

 

Depends on which kind of full wave rectifier you are talking about. If you use one diode from each of the ends and use the center tap as ground, you will get 8 * 1.414 -0.7 = 10.6V.

If you place a full wave bridge across the two ends, leaving the center tap unused, you get 16 * 1.414 = 2 * 0.7 = 21.2V

Bob

 

Depends on which kind of full wave rectifier you are talking about. If you use one diode from each of the ends and use the center tap as ground, you will get 8 * 1.414 -0.7 = 10.6V.

If you place a full wave bridge across the two ends, leaving the center tap unused, you get 16 * 1.414 = 2 * 0.7 = 21.2V

Bob

Oh, I forgot the 8V-0-8V no need to use the full bridge, so only need to reducing 0.7V, thanks.