Frequency Divider Circuit

Thread Starter

karthickkumar

Joined Apr 13, 2008
4
HI All, I want to build a Precision frequency divide by 100 circuit, to divide a 1 KHz TTL pulse to 10Hz TTL. Can any body suggest some good circuit for it.
Please help. I am completely new to electronics.
THanks
Karthick
 

beenthere

Joined Apr 20, 2004
15,819
All you need is two 7490 counters. That's not a circuit, just a bit of TTL logic. Get a data sheet and see how they work.
 

relicmarks

Joined Oct 13, 2006
355
I never understood how a flip flop can take a frequency and divide it down or convert to another frequency , whats the theory behind this please?
 

beenthere

Joined Apr 20, 2004
15,819
Look at a 7474 D flip-flop. If you run the not-Q output to the D input, then the flip-flop will change state every other clock. This has the effect of dividing the clock frequency by 2.
 

SgtWookie

Joined Jul 17, 2007
22,230
I never understood how a flip flop can take a frequency and divide it down or convert to another frequency , whats the theory behind this please?
Basically, you are "hijacking" this thread.

The original poster's request has been satisfied - this is their thread. If they have more questions, they are free to ask more, because it belongs to them.

But in brief, each flip-flop will take the input signal and divide it by two.
 

relicmarks

Joined Oct 13, 2006
355
sorry i didn't mean to hijack his theory

I just don't get how the flip flop divides the input by 2

And maybe others can learn from it too
 

beenthere

Joined Apr 20, 2004
15,819
But, RonH, if you look at the Q output, you will see that it changes at one half the clock frequency and so is performing frequency division.
 

Ron H

Joined Apr 14, 2005
7,063
But, RonH, if you look at the Q output, you will see that it changes at one half the clock frequency and so is performing frequency division.
On the Nth clock, the output changes to a 1.
N+1, 0
N+2, 1
N+3, 0
N+4, 1
etc., etc.
On every clock cycle, the output changes state.
I wasn't disputing the fact that the circuit divides by two. I was disputing your terminology.:D
 

beenthere

Joined Apr 20, 2004
15,819
I was going to link you to the Ebook, but we don't seem to cover flip-flops in it.

Look up the data sheet for a 7474 (or 74LS74, 74Hc74, etc). The Q output follows the D input with each clock. With the not-Q output tied to D, then the state of D will change with each clock, so the device will have an output that changes state at half the clock frequency.

It would make existing threads run a bit better if you would post these questions as separate threads. Hijacking a thread is something like bursting into an ongoing conversation. We do discourage the practice.
 

Caveman

Joined Apr 15, 2008
471
Relicmarks,
It is really simple when you draw it out. Draw a square clock. Notice that a "cycle" is the clock going high, then going low. It is high for a "half-cycle" and low for a "half-cycle".
Now, the flip-flop latches its input onto the output only on the rising edge of the clock. Until the next rising edge, the output does not change. Also, at the same time, the flip-flop latches the inverse of the input onto the inverted output.
To halve the clock, just hook the inverted output to the input. Now here's the other important point. It takes time to transfer the input to the output, so what gets latched to the outputs is the input just before the rising edge of the clock.

Does that do it for you?
 
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