How many flip-flop values are complemented in an 8-bit binary ripple counter to reach the next count value after 11111111 and 01110011?

 

You need to show YOUR best effort to solve YOUR homework problem.

That will give us the necessary starting point from which to help you move in the right direction.

In this case, what are the next count values after the two you are given?

 

Well, my guess is that 11111111 --> 00000000, so all 8 bits of 11111111 are flip flopped.

For B, 01110011 --> 01110100 (Right? I'm not 100% sure...)

The only bits that got flipped were 011 --> 100, so the answer is 3?

Thanks

 

You are correct on both.