Tried, but there seems to be losses that don't effect the gas valve. I even tried without the resistors R1 and R2. It may be the losses in wires that take it down. Also, I've tried higher gate voltages, as per crutschow, and it consistently comes on around a gate voltage of 4V and higher. My guess is that this 'overflows' into the source a bit, reaching the threshold where the gas valve will come on.I connected this circuit using R2 to simulate the TH load with a 3 volt input from the Pico and measured 0.56 volts on the source of the BS170.
So it seems that the circuit should work as shown in post #1 removing the 10K resistor in series with the gate.
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Yup, so applied 10V at gate and it effected the gas valve. I consistently got it to start when coming up from lower voltages to around 4V. So, the 3.3V from PICO is insufficient. I also suspect losses in wires that I'm using between TPTH and TH, so it takes a higher voltage to effect the gas valve.Can you apply 10V to the MOSFET gate and see if that works to close the gas valve?
If so, then reduce the gate voltage until you find the minimum voltage needed.
Those losses are likely small.I also suspect losses in wires that I'm using between TPTH and TH, so it takes a higher voltage to effect the gas valve.
If you don't have 5V available, the look for a logic-level MOSFET with a max Vgs threshold voltage of ≤2V.Back to the drawing board.....
Thanks. This is to be a battery powered circuit. A constant drain on the 5V vsys doesn't look efficient. But thanks again.If you program the GPIO output to normally HIGH this circuit will activate Q2 with 5 volts on the gate when pin 16 goes LOW.
View attachment 307295
Or add the inverter circuit comprised of Q1 and Q2 if the maintaining the logic output on pin 16.
View attachment 307296
Change R1 and R2 to 1M. That's only and extra 8 microamps. Actually R1 can be removed reducing the drain to 5 microamps.Thanks. This is to be a battery powered circuit. A constant drain on the 5V vsys doesn't look efficient.
Awesome, I'll give that a try.Change R1 and R2 to 1M. That's only and extra 8 microamps. Actually R1 can be removed reducing the drain to 5 microamps.
Maybe I'm wrong to call it 'shorting'. If I connect TPTH to TH with a wire, the gas valve opens and the fire lights. So, I suppose, it's more like 'closing' the circuit, which uses power from the thermopile to open the gas valve.I don't know what sort of fire you have, but for all the gas appliances I'm familiar with the thermopile voltage (<1V) can drive an Amp or so through the low-resistance gas valve solenoid to hold the valve open. Shorting out that voltage causes the valve to close and shut off the gas supply. The arrangement you have, or are trying to create, seems the complete opposite of this norm?
The fireplace works and all the hardware works. The remote controller died - two components, the handheld remote control and the receiver which was wired between the TPTH and TH on the fireplace. It is a simple operation, but I am trying to avoid spending hundreds on a new remote controller (which I already did on another fireplace I have) while trying to learn and innovate by creating my own device.The thread starts with a question about powering a fireplace heater gas valve and then starts talking about a power-pile circuit in a stove.
I do not suggest even considering the use of any power pile hardware, valve or thermo-couples.
Is the intention to use a system taken from a stove?
OK, an arrangement that is simpler but not as modern as trying to bias a transistor will be to use a small mechanical relay to do the switching. I know that they are available with five volt coils, I am not sure about 3.3 volt coils. They have very good isolation between control and the contacts, And the voltage drop in the on mode is very low.The fireplace works and all the hardware works. The remote controller died - two components, the handheld remote control and the receiver which was wired between the TPTH and TH on the fireplace. It is a simple operation, but I am trying to avoid spending hundreds on a new remote controller (which I already did on another fireplace I have) while trying to learn and innovate by creating my own device.
Thanks,
Jim.
You mentioned the unit will be battery operated. What is the battery voltage?trying to learn and innovate by creating my own device.
