The answer to the energy is 1.796E-4

I assumed that the circuit is basically two capacitors in series with no voltage source.

My first attempt was simply adding the energy in both capacitors, E = 1/2 (C1V1^2 + C2V2^2) = 1/2 (2u*100^2 + 0.01u*200^2) = 0.0102J, did not get the correct answer

I then took the series equivalent capacitance, C = 9.95 nF, then used the formula E = 1/2 (CV^2) again, but assuming that there is only a 100V potential difference across the circuit, E = 1/2 (9.95n * 100^2) = 4.975E-5 Joules, still didn't get the correct answer. Tried it with other values for V = 200V and 300V and still couldn't get the answer. What am I doing wrong?