I am stuck on this question, that asks me the following :
If R2 is short circuited , the amps in R3 is : ?
Here is what i did :
I redrew circuit without R2. So it becomes a series circuit R1in series with R3
added the resistance. r1 + r3 so 40 +10 = 50
Found the amps so 30v/50 ohm = 0.6 amps
so 0.6 amps times R1 =6 volts on R1 and 30-6 is 24 volts on R3
Since this becomes a series circuit it should be the same current.
What am i doing wrong ?