# Find current using Nortons Theorem

#### Sajan Gurung

Joined Dec 20, 2018
33

#### Jony130

Joined Feb 17, 2009
5,181
For me the Isc is equal to 15A. And your mesh equation are wrong (10A is not a voltage).

#### Sajan Gurung

Joined Dec 20, 2018
33
For me the Isc is equal to 15A. And your mesh equation are wrong (10A is not a voltage).
Oh right!, so from outer loop i would get an eqn and i1 would be 5 and i2 would be 15, ok, thanks!

#### WBahn

Joined Mar 31, 2012
26,143
Is my solution correct to this problem? Is value of Isc 10 jst from the ckt nw?
You completely ignored the advice I gave you here:

and then proceeded to make the same mistake again. Had you bothered to track your units, you would have seen that your equation has two terms that are voltages and one that is current. Thus, right here you would have known that your equation was wrong and you could have fixed it. Instead, you blindly blundered on with a guarantee that your answer would be wrong and so everything you did after this was 100% wasted time and effort.

You ended up with a current for i1 of 12.5 A. By inspection, this then requires that i2 be 22.5 A and therefore the voltage drop across the 4 Ω resistor would be 90 V. Does this make sense?

Okay, so you disregard both pieces of advice and got an answer for the load current of 5 A.