what if my audio has 10k output impedance run to 3 meters unbalance to 10k input impedance. what will happen to my audio? rule of thumb is ratio 10:1

 

Well, it seems like you are making a 2:1 voltage divider so, your signal voltage will be cut in half. The effect of that on power transferred to your downstream unit depends on the input technology (i.e. is the 10k the direct coupling to the base of a bjt or is the 10k a resistor from gate to ground of a MOSFET/JFet, or is it the capacitively coupled with either of the above (including biasing).

We'll need more.

 

I think the "golden ears" might allege that they can hear the difference, but I remain a skeptic on this point. You don't say if the audio is analog or digital, and you provide no other details on the equipment or the cabling, so it is hard to give an accurate answer. What "rule of thumb" are you talking about?

 

I think the "golden ears" might allege that they can hear the difference, but I remain a skeptic on this point. You don't say if the audio is analog or digital, and you provide no other details on the equipment or the cabling, so it is hard to give an accurate answer. What "rule of thumb" are you talking about?

You know, the audiophile rule of thumb that input impendence should be 10x the output impedance.

 

You know, the audiophile rule of thumb that input impendence should be 10x the output impedance.

I guess I missed that one when I worked for Wadia.

 

I guess I missed that one when I worked for Wadia.

That's understandable - back when Digital was the cool thing in audio.
Now, back to the future, I guess.

 

my soundcard has 10k input impedance and my guitar has a dc resistance of 10k

Well, it seems like you are making a 2:1 voltage divider so, your signal voltage will be cut in half.

how about frequency?

I think the "golden ears" might allege that they can hear the difference

yeah now thats why im confuse Lol

 

my soundcard has 10k input impedance and my guitar has a dc resistance of 10k


how about frequency?


yeah now thats why im confuse Lol

Its your amplifier (sound card), you tell me.

By the way, if it sounds good enough for your ears, it usually is.

 

its a soundcard for studio recording, just want to confirm if it degrade the frequency in 3 meter cable and the impedance match
i dont trust my ears anymore it is always dissapoint me, i trust numbers

 

With 10kΩ impedance you would need about 1nF capacitance in the cable to start attenuating high frequencies above 16kHz.
Heck, I can't even hear above 3kHz!

 

With 10kΩ impedance you would need about 1nF capacitance in the cable to start attenuating high frequencies above 16kHz.
Heck, I can't even hear above 3kHz!

speches peaking around 3khz-5khz, sibillance "S" 5-8khz, my wire capacitance is 350pf, just attenuation? or are they gonna ruined or missing some frequency in between? i only care about 40hz-16khz (+/-3db)
so 3 meters is good enough for match impedance ratio 1:1
this audiophile myth ache my balls

 

As gopher suggests, you are not going to hear the difference.
The signal from a guitar pickup might be too low for a soundcard input.
Have you tried it?

 

my soundcard has 10k input impedance and my guitar has a dc resistance of 10k
...

One thing I know with a high degree of confidence is that the DC resistance of the guitar pickup has absolutely no relevance to this problem.
If you can configure a PC as an audio spectrum analyzer you might have a shot at tweaking the soundcard interface relative to a 10K termination resistor. Either that or you can convince yourself that there is no practical thing you can do to improve the situation.

 

The signal from a guitar pickup might be too low for a soundcard input.
Have you tried it?

I tried it. My Les Paul can deliver 1V peak all day, 3V peak if you hammer it.

you would need about 1nF capacitance in the cable to start attenuating high frequencies

Guitar cord measured at 18 pf per foot would need 55 feet to start affecting high frequencies

 

I tried it. My Les Paul can deliver 1V peak all day, 3V peak if you hammer it.


Guitar cord measured at 18 pf per foot would need 55 feet to start affecting high frequencies

Such is the value of an empirical thinker and experimenter.

 

I tried it. My Les Paul can deliver 1V peak all day, 3V peak if you hammer it.

Do I assume that 1V output is a result of active amplification?

 

Such is the value of an empirical thinker and experimenter.

I worked with a band for years. I designed a few novel amplifiers. It was inevitable that I accumulated some information.

Do I assume that 1V output is a result of active amplification?

No. That's a Les Paul guitar plugged into an oscilloscope. 1 meg in an x1 probe. I needed to find the highest output voltage of an electric guitar in order to calculate clipping limits for an input amplifier stage.

Most guitar players piddle around at about 0.1 volt peak, but you need headroom for the moment they hammer a power chord.

 

No. That's a Les Paul guitar plugged into an oscilloscope. 1 meg in an x1 probe. I needed to find the highest output voltage of an electric guitar in order to calculate clipping limits for an input amplifier stage.

That's wicked!

I don't see how a steel string vibrating no more than the width of a horse's hair can generate 1V.
I'm gonna have to put my guitar on a scope and have a look.

 

I don't see how a steel string vibrating no more than the width of a horse's hair can generate 1V.

Look at my post again. I added on to it while you weren't looking.

Most guitar players piddle around at about 0.1 volt peak, but you need headroom for the moment they hammer a power chord.

 

I suppose 1μA x 1MΩ would result in 1V.