Try this

void loop() {
 if(Serial.available() > 0)
{
 val=Serial.read();
 lcd.setCursor (i,0);
 lcd.print(val);
if(++i >= 16)i = 0; 
}

 

First off was it showing up now on the LCD you have to send a byte at time so you break it up into bytes

• Serial.println(1.23456, 4) gives "1.2346"

How do i break it up? hhaha im sorry im not good at this

 

Try this

void loop() {
if(Serial.available() > 0)
{
val=Serial.read();
lcd.setCursor (i,0);
lcd.print(val);
if(++i >= 16)i = 0; 
i get 5115 each time i press the button
}

 

https://www.arduino.cc/en/Tutorial/LiquidCrystalSerialDisplay

It is better to remove the delays in the code.

If this doesn't work when you send

123.23456 at once then you have to use serial interrupt for getting the data into a buffer and then process it and print it.

 

That's because I don't think Jay understands you did the math on the sending side when you add 1.0 that set's the size
Serial.print sends it out one byte at a time. If it's 6 byte it send them all.
Now what you need to do is send the number out raw and on the receiving side do the math
print() will return the number of bytes written, though reading that number is optional

 

That's because I don't think Jay understands you did the math on the sending side when you add 1.0 that set's the size
Serial.print sends it out one byte at a time. If it's 6 byte it send them all.
Now what you need to do is send the number out raw and on the receiving side do the math

"123.4578" is sent one character at a time. It has 8 characters. So, a buffer of 9 will do. Read is using serial interrupt and send it to lcd.print().

 

It you read the core for print it dose stuff for you that why it's so easy to use.
when he put 1023.0 that set's the size to float.
But if you declare you get errors which is what was happening.
But it would be easier if he did the math on the LCD side and send out the value raw
The adc pin reads 1023 so you send say 512 thats 2.5 volts
you print that to the LCD

 

You use this Serial.readBytes(buffer, length)

 

This should do as planned

#include <LiquidCrystal.h>
LiquidCrystal lcd(12, 11, 5, 4, 3, 2);
void setup() {
  Serial.begin(38400);
  lcd.begin(16, 2);
}
void loop()
{
   if(Serial.available() > 0)
   {
   lcd.clear();
   float x = Serial.read();
   float y = x * (5.0/1023.0);
   lcd.setCursor(0, 1);
   lcd.print(y);
   delay(2000);
   }
}

And the send code

int val;
#define button 3
void setup() {
  Serial.begin(38400);
  pinMode(button , INPUT);
}
void loop() {
    val = digitalRead(button);
    if (val == HIGH)
  {
    int sensor = analogRead(A0);
    int voltage0 = sensor;
    Serial.println(voltage0);
    delay(500);
  }
}

 

I sent 512 to it which is 2.50 volts