triggernum5
- Joined May 4, 2008
- 216
Without getting into calculations, a symetrical pattern of pathways is formed, so all indirect currents will cancel out if all resistors are 10ohm..
At A there are 3 possible pathways comprised of 3 10ohm resistors.. At the first vertice in each initial path, there are 2 possible pathways comprised 2 10ohm resistors, and at the next vertice reached there is only one pathway to B comprised of one 10ohm resistor..
So perhaps I'm jumping to a conclusion since I haven't done any math here, but don't the parallel and series configurations of the pathways cancel out making the resistance from A to B 10ohms?
At A there are 3 possible pathways comprised of 3 10ohm resistors.. At the first vertice in each initial path, there are 2 possible pathways comprised 2 10ohm resistors, and at the next vertice reached there is only one pathway to B comprised of one 10ohm resistor..
So perhaps I'm jumping to a conclusion since I haven't done any math here, but don't the parallel and series configurations of the pathways cancel out making the resistance from A to B 10ohms?