hi..i need to do an excercise in this picture.the problem is that i cant find v5 and v6 (that is vc5 and vc6)i found ll the other potentials.i know that the current is the same in Q5 and Q6.i made an equeation for that.(vcc-v5)=2(vcc-v6) but i need another eqution to solve it.iv tried the bjt rules (Vbc=Vce+Vbe)it worked for me in other exrecise where Q5 is grounded and Vs isnt there.but on this exercise i have Vs in Q5 and bjt rules doesnt make the propriete solution.thanks for your help.
does any one knows the name of the circuit?

 

another tiny problem..i found IE1 and IC1 but how i find ic2 ?kcl in the junction.but-assuming the bjt the same.and assuming Ie1=1ma
ic1=IE/b=0.99ma .is the iB1=IB2? in the answer IC2=0.952ma so how the 47microamps gone away?(kcl:ic1=ic2+I |where I is IB2 +IB3)
but IB2 ISNT EQUEL TO IB1.SO HOW THE TEACHER DECIDED THAT IN THE JUNCTION 0.952MA TO IC2 AND 0.047MA TO i=IB2+IB3
THANKS A LOT!!!!!