thanksHi terry,
Welcome to AAC,
Do you have any calculations you could post.?
E
im having difficulty on where to start with this question,Welcome to AAC!
Show your solution so we can see where you're having difficulty.
R1=5k ohmshi,
OK,
What is the resistance of the R2 and R3 in parallel, left side circuit.?
E
But what is the combined resistance of R2 and R3 in parallel?R1=5k ohms
R2= 2k ohms
R3= 6k ohms
so 1/2000+1/6000=1/Rt =1500 ?Hi terry.
Calculate the parallel value of R2 and R3 resistors.??
E
What current does that give for R1 and Rt?so 1/2000+1/6000=1/Rt =1500 ?
You need to get into the habit of properly tracking your units. Treat any dimensioned quantity as the product of a magnitude and a unit and then just apply the normal rules of arithmetic and algebra accordingly.so 1/2000+1/6000=1/Rt =1500 ?
V/R1 = 12/5000 =2.4x10^-3What current does that give for R1 and Rt?
You are making one of the classic mistakes and just throwing whatever V and R you happen to find at Ohm's Law and hoping that the result means something.V/R1 = 12/5000 =2.4x10^-3
V/Rt = 12/1500=8x10^-3
I have no idea what "5000+1500-6500R" is.i was confused if they could be now added in series and have 5000+1500-6500R and then have 12/6500=1.84x10^-3
That's an anti-spammer limitation on New Members that will go away once you get 10 posts.sorry for long reply can only post 5 an hour
when you say add R1 and R23 together, thats what i was meaning by adding the 1500(R23) and (R1)5000 resistor together to get 6500, ?You are making one of the classic mistakes and just throwing whatever V and R you happen to find at Ohm's Law and hoping that the result means something.
Ohm's Law relates the resistance of a resistor to the voltage across THAT resistor and the current through THAT resistor.
The 12 V is NOT the voltage across ANY of those resistors (unless one of them happens to be either 0 Ω).
I have no idea what "5000+1500-6500R" is.
But, yes, once you have the parallel combination of R2 and R3 (let's call it R23 and reserve Rt for the total circuit resistance), then you can add R1 and R23 to get Rt.
That's an anti-spammer limitation on New Members that will go away once you get 10 posts.
That's what I was referring to, it just didn't jive with what you wrote, except R23 is NOT 1500, it is 1500 Ω. Start using units properly -- it could literally save your life some day.when you say add R1 and R23 together, thats what i was meaning by adding the 1500(R23) and (R1)5000 resistor together to get 6500, ?
is that different to what you are talking about ?
yes i see what your saying ,That's what I was referring to, it just didn't jive with what you wrote, except R23 is NOT 1500, it is 1500 Ω. Start using units properly -- it could literally save your life some day.
Another comment I should have made your prior post is that another good practice to always ask if your answers make sense.
Your results claim that the current in R1 is 2.4 mA but that the combined currents in R2 and R3 total to 8 mA, while the current being delivered by the voltage supply is 1.84 mA.
Do those results make sense?
If not, then it's time to step back and not go forward until they do. You've likely make a mistake somewhere. Perhaps it was conceptual (like not properly applying Ohm's Law), or perhaps it was just a silly math error. But it's a big red warning flag telling you to stop and review your work because going forward is most likely only going to be a bunch of wasted effort.
You want to use V/R=I and you are just grabbing the nearest V, which happens to be 12 V, without any regard as to whether that 12 V is actually the voltage appearing ACROSS the 5000 Ω resistor.yes i see what your saying ,
so if i do 12v/6500Ω i get 1.84mA so that should be the total resistance,
if i do 12v/1500Ω i get 8mA so that means that R1 should equal 1.04mA ?
but i would say using ohms law V/R=I and would do 12v/5000Ω to get 2.4mA which like your saying cant be correct im not sure where ive went wrong am i doing the correct calculations and my math is wrong or is the maths correct and using ohms law incorrect ?
by Jake Hertz
by Jake Hertz
by Jake Hertz
by Duane Benson