As per duality theorem, the expression remains valid, if AND<-> OR and 1<-> 0.
If F=x+yz+x'z , the applying duality principle, F= x(y+z)(x'+z). if I try to fill function in truth table, considering first expression as F1 and second one as F2, and using what I have understood, for F1 , RHS will give output as 1 and for F2 , output will be 0. But I am not getting F1 =F2. whereas Duality principle results in correct result for y( evaluated as y='1')= ab+bc+ca and y ( here y='0')=(a+b)(b+c)(c+a). Where am I going wrong?
x y z F1
0 0 0 0
0 0 1 1
0 1 0 0
0 1 1 1
1 0 0 1
1 0 1 1
1 1 0 1
1 1 1 1
x y z F2
0 0 0 0
0 0 1 0
0 1 0 0
0 1 1 0
1 0 0 0
1 0 1 1
1 1 0 0
1 1 1 1
If F=x+yz+x'z , the applying duality principle, F= x(y+z)(x'+z). if I try to fill function in truth table, considering first expression as F1 and second one as F2, and using what I have understood, for F1 , RHS will give output as 1 and for F2 , output will be 0. But I am not getting F1 =F2. whereas Duality principle results in correct result for y( evaluated as y='1')= ab+bc+ca and y ( here y='0')=(a+b)(b+c)(c+a). Where am I going wrong?
x y z F1
0 0 0 0
0 0 1 1
0 1 0 0
0 1 1 1
1 0 0 1
1 0 1 1
1 1 0 1
1 1 1 1
x y z F2
0 0 0 0
0 0 1 0
0 1 0 0
0 1 1 0
1 0 0 0
1 0 1 1
1 1 0 0
1 1 1 1