Hi,
I have a circuit board for a fan delay that has burned out two resistors.
I have drawn the circuit diagram and included it here.
I think it works by closing the switch, this energises the relay and turns the light on (it would run the fan but I have put a light in the circuit here).
When the switch is opened the relay remains closed for a time determined by the potentiometer, as much as 15 minutes I think.
There may be other components burned out but I don't know the values or R3 or R7. could someone help me if they have an idea what the values might be?
An explanation as to how the circuit works would be a great help, I could then follow the signal through the circuit if something else has burned out.
Thank you.
Bob.
There is a possibility I have made an error with my drawing but I have checked and rechecked it.
I have a circuit board for a fan delay that has burned out two resistors.
I have drawn the circuit diagram and included it here.
I think it works by closing the switch, this energises the relay and turns the light on (it would run the fan but I have put a light in the circuit here).
When the switch is opened the relay remains closed for a time determined by the potentiometer, as much as 15 minutes I think.
There may be other components burned out but I don't know the values or R3 or R7. could someone help me if they have an idea what the values might be?
An explanation as to how the circuit works would be a great help, I could then follow the signal through the circuit if something else has burned out.
Thank you.
Bob.
There is a possibility I have made an error with my drawing but I have checked and rechecked it.
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