Direct-Coupled CE Amp - Voltage Gain?

Thread Starter

aac044210

Joined Nov 19, 2019
178
Here is a little gem that I found on line. A direct-coupled CE amp.
I calculated the voltage gain for each stage and for the amplifier overall.
The overall gain is 11,320 and yet LTS results in a gain of 350. 99% of
vs enters the first stage but I can't figure out why the gain is so low.

Any suggestions?
 

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ericgibbs

Joined Jan 29, 2010
21,442
hi aac,
Do you have a link to the online circuit, RE2 looks a high value..
What did your maths say for the gain of the 1st stage.??

E
 

Jony130

Joined Feb 17, 2009
5,598
Well, let me try.

From LTspice we know that Ic1 = 323μA and Ic2 = 423μA

The second stage gain is Av2 ≈ 38*Ic2 *Rc = 38*423μA*10kΩ ≈ 160 V/V

And the input impedance of a second stage is Zin2 = β/gm = 300/(38*423μA) = 18.66kΩ

The first stage gain is Av1 ≈ (Rc1||Zin2)/(RE1) = 2.1 V/V

Hence the overall voltage gian is Av = 2.1*160 = 336 V/V
 

Thread Starter

aac044210

Joined Nov 19, 2019
178

Jony130

Joined Feb 17, 2009
5,598
But lack of this capacitor is the reason why your calculation does not match the LTspice result.
Because without this capacitor (Ce1) the first stage gain is very low Av1 = (Rc1||Zin2)/( RE1+re1 ) compare to the situation when you include this capacitor Av1 = (Rc1||Zin2)/re1
 

Thread Starter

aac044210

Joined Nov 19, 2019
178
But lack of this capacitor is the reason why your calculation does not match the LTspice result.
Because without this capacitor (Ce1) the first stage gain is very low Av1 = (Rc1||Zin2)/( RE1+re1 ) compare to the situation when you include this capacitor Av1 = (Rc1||Zin2)/re1
If you put the RE1 bypass cap into the circuit, the gain is nuts and the amplifier is useless.
Why would they even show such a circuit?

I have re-calculated my gain as attached.
 

Attachments

Thread Starter

aac044210

Joined Nov 19, 2019
178
Well, let me try.

From LTspice we know that Ic1 = 323μA and Ic2 = 423μA

The second stage gain is Av2 ≈ 38*Ic2 *Rc = 38*423μA*10kΩ ≈ 160 V/V

And the input impedance of a second stage is Zin2 = β/gm = 300/(38*423μA) = 18.66kΩ

The first stage gain is Av1 ≈ (Rc1||Zin2)/(RE1) = 2.1 V/V

Hence the overall voltage gian is Av = 2.1*160 = 336 V/V
In your Av2 calc where did the "38" come from?

Why does Av2 = RC2 / r'e2 not work?

aac
 
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