Hi
a) Calculate the capacity of an electrolytic capacitor (Tolerance 20%). V0 of the capacitor is 33V, the voltage after discharging is V1=30V, the supplied current should be 100A for 100us
b) Also calculate the minimal capacity required so that there is enough capacity for discharging until the capacitor reaches the end of its useful life (assume 2000h at 105°C with deltaC/C = +-45%).
a)
First I calculated the capacity required for the discharge of 3V.
Q = 100us*100A = 10mC
C = Q/3V = 3.33mF (which is correct according to the solution)
next is b)
The capacitance changes by +-45% during its useful life at 105°C but why is there a plus and a minus here ?
The solution says 3.33mF = C * 0.8 * 0.55 solved for C it gives 7.58mF so they assumed both tolerance and the capacitance change over time to be lower but why ?
a) Calculate the capacity of an electrolytic capacitor (Tolerance 20%). V0 of the capacitor is 33V, the voltage after discharging is V1=30V, the supplied current should be 100A for 100us
b) Also calculate the minimal capacity required so that there is enough capacity for discharging until the capacitor reaches the end of its useful life (assume 2000h at 105°C with deltaC/C = +-45%).
a)
First I calculated the capacity required for the discharge of 3V.
Q = 100us*100A = 10mC
C = Q/3V = 3.33mF (which is correct according to the solution)
next is b)
The capacitance changes by +-45% during its useful life at 105°C but why is there a plus and a minus here ?
The solution says 3.33mF = C * 0.8 * 0.55 solved for C it gives 7.58mF so they assumed both tolerance and the capacitance change over time to be lower but why ?
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