i didn't understood this circuit...need help!Yep here you have:
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i didn't understood this circuit...need help!Yep here you have:
Scott, can you post a schematic of theNE555 → 8 bits Counter(CD4520) → 4bits sinewave DAC (16 digits)
The resistors as 10K,20K,40K,80K,80K,40K,20K,10K
NE555 → 16 bits Counter(CD4520) → 8bits sinewave DAC (256 digits)
The resistors as 1K,2K,4K,8K,10K,20K,40K,80K,80K,40K,20K,10K,8K,4K,2K,1k
8bits sinewave DAC (http://www.lennard.net.nz/electronics/dac.html#r2r)
?4bits sinewave DAC (16 digits)
The resistors as 10K,20K,40K,80K,80K,40K,20K,10K
Ron H, the method almost there, the linked page is only 4 bits(16 digits), the waveform will be only low to high, so it needs to adding the waveform from high to low, that's why I want to using 8 resistors.Scott, can you post a schematic of the
4bits sinewave DAC (16 digits)
The resistors as 10K,20K,40K,80K,80K,40K,20K,10K
?
I can't see how it works.
If you replace the EEPROM with RAM and make the clock adjustable you have the innards of an arbitrary waveform generator.Square wave → 8 bits Binary counter → sine wave EEPROM → 8bits DAC → Op Amp Waveform shaping → sine wave
by Duane Benson
by Duane Benson