This is my next exam paper which has left my cohort stumped.
a) Initially, the diode D3 is not connected (replaced by open circuit). What is the max value of voltage Vo(t)? Is the diode D7 forward or reverse biased at this point? Explain whether this corresponds to the maximum power dissipated at the diode. Determine the max power dissipated at the diode.
b) Both diodes are now connected as shown in Fig Q3. Each diode has a max power dissipation of 1/8 watt. What is the max allowable amplitude Y of Vi(t)?
I dont understand the concept in (a). When D7 is reverse-biased, how can there be current conducted In that case, how can there be power? In that case, how can there be a max power???
When both diodes are connected, how does the current flow? Does it go through one and then the other? Do give me a hint. Thanks
Note : the diagram states that Vi(t) = 5 sin (2∏t)V, R2 = 100Ω, D3 forward voltage = 0.3 V and that D7 forward voltage = 0.7V. Vo(t) is the voltage across D7.
a) Initially, the diode D3 is not connected (replaced by open circuit). What is the max value of voltage Vo(t)? Is the diode D7 forward or reverse biased at this point? Explain whether this corresponds to the maximum power dissipated at the diode. Determine the max power dissipated at the diode.
b) Both diodes are now connected as shown in Fig Q3. Each diode has a max power dissipation of 1/8 watt. What is the max allowable amplitude Y of Vi(t)?
I dont understand the concept in (a). When D7 is reverse-biased, how can there be current conducted In that case, how can there be power? In that case, how can there be a max power???
When both diodes are connected, how does the current flow? Does it go through one and then the other? Do give me a hint. Thanks
Note : the diagram states that Vi(t) = 5 sin (2∏t)V, R2 = 100Ω, D3 forward voltage = 0.3 V and that D7 forward voltage = 0.7V. Vo(t) is the voltage across D7.
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