Im tryng to
Given the following IIR filter equation:

y(n) =0.0181x(n) -0.0543x(n-2) +0.0543x(n-4) - 0.0181x(n-6) + 2.942y(n-1) -4.702y(n-2) +4.634y(n-3) -3.077y(n-4) +1.2466y(n-5) - 0.278y(n-6)

Determine and write out the equation for H(z)

all I know is Hz=Yz/Xz

 

Im tryng to
Given the following IIR filter equation:

y(n) =0.0181x(n) -0.0543x(n-2) +0.0543x(n-4) - 0.0181x(n-6) + 2.942y(n-1) -4.702y(n-2) +4.634y(n-3) -3.077y(n-4) +1.2466y(n-5) - 0.278y(n-6)

Determine and write out the equation for H(z)

all I know is Hz=Yz/Xz

Hi,

Have you done at least one convolution yet?
Try to reverse the process.

 

Start separating the input coefficients and output coefficients.

 

https://ccrma.stanford.edu/~jos/fp/Z_Transform_Difference_Equations.html

http://web.mit.edu/jorloff/www/18.03-esg/notes/extra/differenceEq.pdf



Regards, Dana.