i have not yet calculated the exact value but around 420 mA of current would be fine. i will be powering it through external regulator which is 24v/2.5A O/PHow much current do you need out of the 24 V output?
What power source is available to power this output circuit?
ak
For that you want a higher current diode for the circuit I posted, such as a 1N400x (x = 1 through 6) or a Schottky diode such as the 1N5818 (which has a slightly lower forward voltage drop).around 420 mA of current would be fine
Thanks... i replaced it with schottky diode. I am still not sure it will work or not ... will test this thing and let you guys know.For that you want a higher current diode for the circuit I posted, such as a 1N400x (x = 1 through 6) or a Schottky diode such as the 1N5818 (which has a slightly lower forward voltage drop).
It still is not clear to me if there is a single, common GND for all input signals, output signal, and power. Because of this, here's my suggestion.i have not yet calculated the exact value but around 420 mA of current would be fine. i will be powering it through external regulator which is 24v/2.5A O/P
Exactly what I was getting at many posts ago. I asked if the inputs and outputs had a common or were isolated, and TS answered that is neither. I don’t think he understands what a common ground is, or what is meant by isolation.It still is not clear to me if there is a single, common GND for all input signals, output signal, and power. Because of this, here's my suggestion.
Three optocouplers, one for each input. The three output transistors in parallel drive a PNP power transistor (or power darlington) as the output switch. LEDs in series with each opto output will give an indication of which one is on. Schematic later, unless someone else wants to whip up one..
ak
Only if the three "sensors" make up only one electronic assembly. If they are three separate assemblies with independent power sources, then who knows.He now says all the outputs come from a single chip, which implies they have a common ground.
Yes, they will have common ground.Exactly what I was getting at many posts ago. I asked if the inputs and outputs had a common or were isolated, and TS answered that is neither. I don’t think he understands what a common ground is, or what is meant by isolation.
He now says all the outputs come from a single chip, which implies they have a common ground.
We need to determine if this s true and if the output also shares a commonground before we can give a solution.
TS, if you understand what I am talking about, please inform us about the grounds. If not, tell us what you don’t understand.
the wires should handle 0 to 24v , because inputs gonna give 24v supply when system activates and i need it to pass to output which is a spray module of 10 watts, 24vdc which in fact activates spray (water)Only if the three "sensors" make up only one electronic assembly. If they are three separate assemblies with independent power sources, then who knows.
The 2803 has 8 NPN open-collector darlington transistors with all of the emitters tied together. If this really is the output stage of a sensor module/assembly/whatever, then the output goes high by being pulled up when a transistor is turned off. This now raises the question of how much current is available to drive something like an optocoupler input.
OR
The sensor output is one stage of a 2803 that goes low on "sense". In the state where the TS says the output is 0 V, the actual case is that both output pins are at 24 V; one direct connect and one pull up resistor to a turned-off 2803 section.
I was gonna do a schematic, but now I'm holding off; still too many questions.
ak
Okay, then all you need is a diode from each input to the output.Yes, they will have common ground.
i output current from each channel of 2803A is around 30 to 300 mA. but after that there are many resistors and diodes so there will be drop in the value. I am not worried about the drive current right now. I am trying to build a schematic of what components to use and how to workout the logic. Later on while testing, we can change accordingly.Only if the three "sensors" make up only one electronic assembly. If they are three separate assemblies with independent power sources, then who knows.
The 2803 has 8 NPN open-collector darlington transistors with all of the emitters tied together. If this really is the output stage of a sensor module/assembly/whatever, then the output goes high by being pulled up when a transistor is turned off. This now raises the question of how much current is available to drive something like an optocoupler input.
OR
The sensor output is one stage of a 2803 that goes low on "sense". In the state where the TS says the output is 0 V, the actual case is that both output pins are at 24 V; one direct connect and one pull up resistor to a turned-off 2803 section.
I was gonna do a schematic, but now I'm holding off; still too many questions.
ak
Please post a partial schematic of the sensor, showing the output stage and components. This will save a lot of time.output current from each channel of 2803A is around 30 to 300 mA. but after that there are many resistors and diodes
i Tested with Diodes , I am getting an output voltage of .152 only, i need 24v nearby.Okay, then all you need is a diode from each input to the output.
Please have a look. The input signal to new circuit will be signal 1 and common gnd.Please post a partial schematic of the sensor, showing the output stage and components. This will save a lot of time.
ak
its a power mosfet, IRFR9024NTRPBF . please check the datasheet attached for mosfet. PTC cold value is 0.5 ohm. 24v supplies the current i need to power the spray module. no external source is connected seperatley to spray circuit.What is the value of the unmarked zener diode?
What is the current rating of the unmarked p-channel MOSFET?
What is the cold value of the PTC?
Can the 24 V source in this schematic supply the current you need to power the spray module, or does the power for the spray module come from a different voltage source?
ak
i tested with different diodes, but output is .150 v. i think i will need a optocoupler to power it to 24vI tested
i Tested with Diodes , I am getting an output voltage of .152 only, i need 24v nearby.
Then you connected it wrong. Show us how.i tested with different diodes, but output is .150 v. i think i will need a optocoupler to power it to 24v
Check this, i am testing 2 modules for now . So did not connect third one. The diodes are connected properly in right direction and then combined with resistance.Then you connected it wrong. Show us how.
i was testing and i found that due to resistor 10k 0.152 v was the output. I tried 100 ohm and got 9 v o/p . still i need 24v but when i tried 50 ohms it did not work.Then you connected it wrong. Show us how.