It is NEVER a good move to prove to a prospective employer his mistake.It's a great interview question, since the only right answer is to reject the question. Recognizing when you cannot and should not supply an answer, just because your boss is asking for one, is true wisdom. That's a valuable skill few possess.
I agree. Were I to give such a problem (and two of my standard interview question are in this direction), I'm primary interested in seeing if the person recognizes that an issue exists and then seeing how they go about dealing with it. I'm not looking for any specific answer, just an approach that is rational and consistent while keeping in mind that the person is being asked to think on the fly in a stressful situation.It's a great interview question, since the only right answer is to reject the question. Recognizing when you cannot and should not supply an answer, just because your boss is asking for one, is true wisdom. That's a valuable skill few possess.
Ah, but now you are reading information into the problem that is not there.Last comment: the short wins and the meter passes no current, though I admit there is a singularity at the point of infinity that I do not possess sufficient analytical skills to compute the transfinite quantities. Specifically, can infinity times zero equal some constant? If so, the meter reads current.
(I'm going to pose that question in the Mathematics forum.)
That's what I got!Yes, but this is contradictory.
If the short is zero resistance the power supply cannot read 50.00000 volts!
Excellent summary of the intent of the question....I'm primary interested in seeing if the person recognizes that an issue exists and then seeing how they go about dealing with it. ....
If they are looking for something like, "None, it's free to go up," or "No amount because the top isn't open to the public," then that I would put into the category of useless "brain teaser" type questions."How many quarters does it take to reach the top of the Empire State building?".
That question doesn't mention stacking quarters.
Ah, but some would argue that since zero is a real and well defined quantity, that we have a voltage divider with to equal resistors and thus the voltage across the branch with the resistor and ammeter obviously has 25V across it.
by Jake Hertz
by Jake Hertz
by Aaron Carman