Draw the circuit to Convert square wave to DC, As the frequency increases the DC amplitude should increase.
Conversion of square wave to DC.
- Thread starter justin_555
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No, it shouldn't.
The DC value of a symmetrical square wave is 50% of its peak value, no matter what the frequency is. If the send half of the question is correct, then the first half is not stated correctly. The entire question is correct for a rectangular waveform that is pulse-width modulated or pulse-position modulated.
Of course it is possible to convert a frequency-modulated square wave to a DC value that increases as the frequency increases - that is what an FM radio does. Does the instructor want you to design an FM detector?
If not, there is a large difference between converting a square wave to its equivalent DC value (using a lowpass filter) and its peak DC value (using a rectifier).
Two questions for the instructor:
1. Is it a symmetrical square wave?
2. Average or peak DC value?
ak
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That's an awfully sketchy description of what you're looking for, and leaves a lot of room for (mis)interpretation. I'll make a wild guess here and assume you want a frequency-to-voltage converter, also known as a tachometer circuit.
There is no "the" circuit for a F-to-V converter; there are many, MANY possible designs. This Google Images page shows scores of possibilities.
Is this a homework assignment or a request for s project?
Justin,
first step is to make a formulae of the sq wave output power input should be amplitude, offset, % on in one period and frequency.
When you observe your formulae you will detect dependencies in power which is a direct link to the output voltage.
Next step is to convert this signal into a DC.
Ask yourself the question how can I store these 'pulses' and what do I need to do so and more important what electronic component will do this for me?
So get your brand new brains out of the package and start pestering it with foresaid questions.
Picbuster
