Contradictory equations in BJT

Thread Starter

Fethi

Joined Nov 23, 2017
2
Hello,

I have a problems with equations in bjt.Let me explain with an example :

upload_2017-11-25_19-36-5.png
Circuit

It is clear that the base current depends on RB by mesh analysis :

upload_2017-11-25_19-38-27.png
Mesh-analysis

However if we think about the collector current formula which is Ic = Is . e^(Vbe/Vt)

In this formula Is, Vbe and Vt are constant.(at least for ideal bjt).So collector current is constant.Then , base current is constant(Ic=β.Ib).Finally emitter current is also constant because it is sum of base and collector current.As a result, there is no importance of resistance in circuit for currents.Because currents are already determined by formula.I know this is not true but I couldn’t find an explanation.Can you help me?

Thank you,

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hobbyist

Joined Aug 10, 2008
892
The transistor is considered a current source, according to the equation, therefor the resistor RC is not used to limit collector current, but rather used to develop a voltage across it with respect to the voltage across the transistor.
The transistor and RC form a variable voltage divider.
 

crutschow

Joined Mar 14, 2008
34,468
Vbe and Vt are constant.(at least for ideal bjt).
Vt is constant but Vbe is not constant.
It depends upon the base current which is determined by Rb.
The base emitter voltage is basically a forward diode drop as given by this equation where I is the base current and V is Vbe:
upload_2017-11-25_9-41-27.png
 
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