common emitter amplifier

Jony130

Joined Feb 17, 2009
5,487
I can do a quack check

Vb ≈ 6* 250/(250 + 75) ≈ 4.6V and Ie ≈ (4.6 - 0.7)/0.7 ≈ 5.56mA. But Ie_max = 6/(1 + 0.7) = 3.5mA
and because Ie>>Ie_max transistor is in saturation.
But if we do more precise calculations I find
Ie = 3.08mA and Ic = 100/101 * 3.08 = 3.05mA
Vce = 6 - 1*3.05 - 0.7*3.08 = 0.794V Transistor is on the edge of a saturation, very poor design.
And the gain is around -36V.
 
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