It looks like Vth for th
e first circuit is 5.6V and 22V for the second one. But I do not see how this can help you with your midterms.
What is the direction of the current that is flowing through R1 (16Ω) resistor ?could u explain it ?? coz i think Vth1 = .8 .. the resestance is in series with the voltage source and the other is series with the current source
Vth2 = Va - VbVth2 = 18-4 =14 not 18+4... what do u think ?
in R16 .. i think it lies in the same loop of the current source so the current at 16 would go left then down then right then up or that's what i think according to the geometry of the problemWhat is the direction of the current that is flowing through R1 (16Ω) resistor ?
Vth2 = Va - Vb
Va is ??
And Vb is ?? If the reference point (0V GND) is at negative terminal of a 4V voltage source.
Ask yourself whether you would expect there to be any change in the current flowing in the load if the 10 V source in that bottom branch were changed to 10 kV. If the answer is yes, then it will affect Vth.i was wondering whether the lowest branch in this problem would affect the Vth or not
yes indeed it's the same .. but most of the time they stick the final answer to any problem to check whether it's right or wrong .. this book doesnt :\Thanks for the image. It's not very readable and many people will not go out to third-party sights to see an image. It is far better, for several reasons, to take your image and use a basic image editor (such as Paint) to rotate it and scale it to about 300 pixels to 600 pixels wide and save as a JPG or PNG (JPG in this case, since it's a picture) and then upload it to this site (so that it will be archived along with your post and therefore accessible years from now regardless of what happens to the third-party site).
I've never heard of "delmar circuit analysis," but wouldn't the answer have to be the same as by any other method?
A good text should do both to help your skills and confidence evolve. The real world is not going to supply answers to the problems you work, so it only hurts if your text never expects you to develop the ability to check the correctness of your answers from the answers themselves.yes indeed it's the same .. but most of the time they stick the final answer to any problem to check whether it's right or wrong .. this book doesnt :\
You should still upload it here, not on some third-party site. There is no way to know if a third-party site is going to try to install malware on your machine, so it's not worth the risk for most of us. I went ahead and made an exception and took a look and your solution to the second problem is fine, though you should indicate that you are finding Vab and not Vba (these are different things).
A good text should do both to help your skills and confidence evolve. The real world is not going to supply answers to the problems you work, so it only hurts if your text never expects you to develop the ability to check the correctness of your answers from the answers themselves.
You should still upload it here, not on some third-party site. There is no way to know if a third-party site is going to try to install malware on your machine, so it's not worth the risk for most of us. I went ahead and made an exception and took a look and your solution to the second problem is fine, though you should indicate that you are finding Vab and not Vba (these are different things).
In the first problem you say that Vab = |Va - Vb|. This is not the case. Vab could be negative. Vab = Va - Vb, period.
You also seem to be claiming that Vb is 2.4 V. What is the basis for that? Remember Va and Vb are the voltages at nodes A and B, respectively, relative to a common reference point. What is your common reference point?
by Duane Benson
by Jake Hertz
by Jake Hertz
by Jeff Child