This is exactly how my professor formatted the question:
For the circuit shown below, calculate:
(a) Thevenin Voltage (Vth)
(b) Thevenin Resistance Rth
(c) Load current ( IL )
this is what I got but I'm not sure what I'm doing wrong:
Vt= 10.9V  0.9 V= 10 V
1. Vth= R2xVt/(R2+R1)
2. Vth= 600 x 10/600+400= 6000/1000= 6 V
3. Rth= R1+R2= 400+600= 1kohm
4. IL= Vth/RL+Rth= 6/1+1= 3mA
For the circuit shown below, calculate:
(a) Thevenin Voltage (Vth)
(b) Thevenin Resistance Rth
(c) Load current ( IL )
this is what I got but I'm not sure what I'm doing wrong:
Vt= 10.9V  0.9 V= 10 V
1. Vth= R2xVt/(R2+R1)
2. Vth= 600 x 10/600+400= 6000/1000= 6 V
3. Rth= R1+R2= 400+600= 1kohm
4. IL= Vth/RL+Rth= 6/1+1= 3mA
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