R7 value has to be calculated ?This is not the whole circuit. After you add the transistor then you will get what you need. Plus it might be good to do the following circuit.
I will test the circuit in Proteus later.
R7 value has to be calculated ?This is not the whole circuit. After you add the transistor then you will get what you need. Plus it might be good to do the following circuit.
But what load current for 3.3V zener ? Sufficient current to keep ESP8266 On while battery is charging ?This is from Orcad
Ok. I will check the circuit tonight but why not use a specific regulator and charger IC deviced specifically for battery operated device which consume very less power ?The current from the zener is only enough for the zener to work. Its in the datasheet. The diode will need a certain amount of current to keep the voltage stable.
The current from the transistor will come from up. The resistor for the current from the transistor. Keep in mind Kirhov;s law, all currents in must be equal to all currents out. Meaning you will get from the 100Ohm in my circuit enough for the zener, but everything else for the transistor has to come from up. After which there will be amplification by the transistor and this will be the current applyed on the load.
Ok. I will check. Here is the circuit I made. I have to test it on hardware with ESP8266. The regulator I chose can provide max 300 mA current but in simulation results are not good.I think I made a mistake up, so here is the latest circuit, I have began to forget as well:
I will redraw your circuit and add meters and test it later.If you are charging the battery you are right, the voltage should be "4,3V". I dont know for Li-On batteries, but normally it should be charged at "4.3V" and discharged at "3.7-3.8V".
Yes, Charger output will be in parallel to battery. Voltage is always applied in parallel to power pins.Thank you guys. The information has been helpful. But a parallel connection of the battery, load(esp8266) and charger is it correct?
So what it means is that the battery is also being discharged with the esp8266 or is the supply voltage coming from the charger?Yes, Charger output will be in parallel to battery. Voltage is always applied in parallel to power pins.
First comes charger then battery in parallel to charger. Then comes 3.3V regulator in series with V+ of battery and then comes ESP8266 across V+ and GND.
If the charger is On all the time then battery will be getting charged and not discharged. Regulator will be getting power directly from charger and providing 3.3V output.So what it means is that the battery is also being discharged with the esp8266 or is the supply voltage coming from the charger?
My reason for asking this question is that i noticed that the esp8266 works well on battery till i switch on the charger. The esp8266 starts to misbehave(endlessly reloading the web address page)
by Jake Hertz
by Jake Hertz
by Aaron Carman
by Jake Hertz