hello friends..
I often sees amplifiers using various capacitor arrangements for filtering the audio spectrum for passing specific frequency levels and I never knew how to change it according to our need. So to learn about it I thought of using a LA4440 amplifier circuit in bridge mode (which is capable of delivering 19W at the output) to drive a sub woofer. On looking at the datasheet I saw the description about the capacitors used in the circuit but I found it very hard to understand as I'm not good in electronics. So could anyone help me with the capacitor values & the method for its calculations?? I'm attaching the circuit and the description in the datasheet.

 

The capacitor in series with the speaker impedance determines the low frequency rolloff.
Thus for a -3dB rolloff at 20Hz and an 8 ohm speaker, the minimum series capacitance would be 1 / (2π*20*8) = 995μF.
For two capacitors in series, (C7 and C8), each would need to be double that value or ≈2000μF each.

But note that 19W is not very much for a subwoofer.
You're not going to get strong bass with that.

 

The capacitor in series with the speaker impedance determines the low frequency rolloff.
Thus for a -3dB rolloff at 20Hz and an 8 ohm speaker, the minimum series capacitance would be 1 / (2π*20*8) = 995μF.
For two capacitors in series, (C7 and C8), each would need to be double that value or ≈2000μF each.

But note that 19W is not very much for a subwoofer.
You're not going to get strong bass with that.

Thank you crutschow for you help. So would the problem be solved by replacing the caps with a standard 2200uf caps ??
"But note that 19W is not very much for a subwoofer." yea I guess so sir. since this is an experimental project I'm exited to know what it could deliver within its limits, So I'm planning to move forward with it.

 

So would the problem be solved by replacing the caps with a standard 2200uf caps ?

That should work fine.