# Can't find unkown resistor value in series-parallel circuit

#### Xannolc

Joined Oct 12, 2017
2
Good day all. I find myself stumped on what i expected to be an easy question. My issue is with the unknown resistor value in the attached documents. I've tried working it out multiple times but i always seem to be missing something. If anybody could help nudge me in the right direction, that would really be appreciated. I've attempted working out the other questions but everything seems to revolve around that one component. Hopefully I'm just overthinking things and overlooking a tiny detail.

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#### BR-549

Joined Sep 22, 2013
4,928
The first image is impossible to read.

#### bertus

Joined Apr 5, 2008
22,120
Hello,

I used the levels function of the GIMP, to get a somewhat better viewable image:

Bertus

#### Xannolc

Joined Oct 12, 2017
2
Sorry about that. hopefully this helps

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#### dl324

Joined Mar 30, 2015
15,460
Sorry about that. hopefully this helps

Check your work on the answer that resulted in a negative resistance.

#### WBahn

Joined Mar 31, 2012
27,900
Good day all. I find myself stumped on what i expected to be an easy question. My issue is with the unknown resistor value in the attached documents. I've tried working it out multiple times but i always seem to be missing something. If anybody could help nudge me in the right direction, that would really be appreciated. I've attempted working out the other questions but everything seems to revolve around that one component. Hopefully I'm just overthinking things and overlooking a tiny detail.
You have near the top of your work Ir = It * r = 1 * 2 = 2A

What is Ir? How is a current multiplied by a resistance equal to a resistance? Where is it that you are claiming that 2 A is flowing in this circuit?

Where does the claim that Rparallel = 6Ω - 4Ω come from?

#### RBR1317

Joined Nov 13, 2010
706
This is how I would label the circuit diagram prior to making any calculations...

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