hi Seyam,
Welcome to AAC.
Please show your work so that we can check for errors .
E

 

hi Seyam,
Welcome to AAC.
Please show your work so that we can check for errors .
E

i have tried to solve it but i couldn't, can you just give me a hint where to start?

 

You have two known current values, 4A and 2A current sources. That means you already know two mesh currents, Ia and Ib.
I1 = Ic-Ib. Apply KVL on Ic mesh. You'll see how easy it goes.

 

You have two known current values, 4A and 2A current sources. That means you already know two mesh currents, Ia and Ib.
I1 = Ic-Ib. Apply KVL on Ic mesh. You'll see how easy it goes.

thank you so much for your reply but can i use mesh analysis sense the question specified the solving method?

i completed the solution using mesh and my answer is

I1 = -0.18A

is it right?

 

thank you so much for your reply but can i use mesh analysis sense the question specified the solving method?

i completed the solution using mesh and my answer is

I1 = -0.18A

is it right?

Yes, it's right I1= -0.18A.
Well, Mesh Analysis implies KVL usage.

 

thank you so much for your reply but can i use mesh analysis sense the question specified the solving method?

i completed the solution using mesh and my answer is

I1 = -0.18A

is it right?

Mesh analysis is fundamentally just a systematic way of applying KVL in such a way that the KCL constraints are intrinsically satisfied.

But, having said that, you should be able to solve the circuit using KVL and KCL directly since this is the kind of circuit that you would typically be expected to be able to solve just before learning about mesh and nodal analysis. So if you can't, then you probably should take some time with it until you can do so and do so in a confident manner. Otherwise you risk putting yourself in a situation where when you apply something like mesh analysis you are really only regurgitating memorized steps without much in the way of comprehension of the underlying principles.

 

thank you so much, that was really helpful,

i have one more circuit that i couldn't figure it out can you please take a look on it?

 

Mesh analysis is fundamentally just a systematic way of applying KVL in such a way that the KCL constraints are intrinsically satisfied.

But, having said that, you should be able to solve the circuit using KVL and KCL directly since this is the kind of circuit that you would typically be expected to be able to solve just before learning about mesh and nodal analysis. So if you can't, then you probably should take some time with it until you can do so and do so in a confident manner. Otherwise you risk putting yourself in a situation where when you apply something like mesh analysis you are really only regurgitating memorized steps without much in the way of comprehension of the underlying principles.

i guess so because this is a past midterm and i have to solve the circuit using the method in the question not any other method, if so can you please give me a hint?

 

i guess so because this is a past midterm and i have to solve the circuit using the method in the question not any other method, if so can you please give me a hint?

You already know the answer. Try KVL and KCL directly to see if you get the same answer. I guess you don't want to hear the word Mesh for now.

For your second circuit, take into account that you already know V1 value, which is 5V for the ground as reference node.
Also, the signs of the 10V source can't be appreciated.

 

thank you so much, that was really helpful,

i have one more circuit that i couldn't figure it out can you please take a look on it?

View attachment 162655

You haven't given us anything to look at!

YOU need to show YOUR best attempt to solve the problem, even if it's wrong and even if it's incomplete. That gives US something to work from so that we can help you identify where you are going wrong and how you might get back on track.

Can't you at least identify the nodes in the circuit and make some attempt to write a node equation for each of them?

If not, and if you are unwilling to go back on your own and get back up to speed, then your best course of action is probably to drop the course you are currently taking and retake the prior course, paying more attention to the things you now know are important.