Could any body help me out to solve attached circuit of diode and transistor !!!
Attachments
-
28.3 KB Views: 44
Is this homework?Could any body help me out to solve attached circuit of diode and transistor !!!
Why do you think so? I would say that Ib=(Vbb-0.7)/Rb, and Ic=Ib*hFE and I can´t see any reason for CE to avalanche.Question 2:
Ib = Vbb / Rb
= 5 / 47 k
= 106 uA
Ic = ∞
Of course, the C-E junction has just avalanched, shorting the B-E junction, and an infinite current is flowing through the collector. Why do they teach kids these inoperable and useless circuits ?
0 for 2.Question 2:
Ib = Vbb / Rb
= 5 / 47 k
= 106 uA
Ic = ∞
How about you don't do that?You got me. Rash. But I have never seen a common emitter circuit without a collector resistor, but then again, even after years of uni, I don't think I understand that circuit.
After thought, I kind of knew this was an exam question, and decided to 'throw a spanner in the works'. As I do ?