I'm trying to figure out how to calculate ripple amperage but I cant find any good formulas for what I want to do. I want to smooth the output through a full bridge rectifier where the input is 240v ac and the current draw around 50 amps. The reason is because it was originally meant for 3 phase so it would have had alot less ripple then my single phase input. I found a formula for figuring out the ripple voltage.
So if I used a 18,000 uf capacitor such as this one https://www.mouser.ca/ProductDetail...Z1n0r9vR22YqjN7vGN3ZSV9u2P47iI0pNPC1xmjIBdg==
Using the formula I found:
Vripple = I / ffc
Vripple = 50 / (120 x 0.018)
I get 23v. Probably good enough for my application. But I cant figure out how to calculate the ripple current in the capacitor. One source seemed to indicate you could use roughly half the load current. So if load current is 50amps what would the ripple current be? That particular cap has a ripple current rating of 27.8A. If I put 2 of them in parallel does that double my ripple current? Is it possible for the ripple current be higher then what the load is?
So if I used a 18,000 uf capacitor such as this one https://www.mouser.ca/ProductDetail...Z1n0r9vR22YqjN7vGN3ZSV9u2P47iI0pNPC1xmjIBdg==
Using the formula I found:
Vripple = I / ffc
Vripple = 50 / (120 x 0.018)
I get 23v. Probably good enough for my application. But I cant figure out how to calculate the ripple current in the capacitor. One source seemed to indicate you could use roughly half the load current. So if load current is 50amps what would the ripple current be? That particular cap has a ripple current rating of 27.8A. If I put 2 of them in parallel does that double my ripple current? Is it possible for the ripple current be higher then what the load is?