Yeah it is a homework. I know the basics of circuit analysis as you mentioned above, its just that I was unsure what equations to start with. If someone would be able to quickly write down the three or four starting equations I can take it from there. Thank you for the help.Looks like homework. Is it? If so, I can move it to Homework Help where it will get more attention.
What analysis techniques have you been introduced do so far? I presume you know Ohm's Law and KVL/KCL, have you learned node voltage and mesh current analysis? Superposition?
In general, it is best if you show YOUR best attempt to solve the problem. That let's us see how you are approaching things, what kind of techniques you seem to be trying to use, and where you are going right and wrong. Then we can make observations and offer hints and suggestions to help you move from where you are to where you need to get.
OK, but suppose the current in V3 is a different mesh current. Then the two mesh currents, I1 & I2, only overlap in the V1 source, making this a particularly easy problem to solve. There is no need to even write the mesh equations.News flash: The current in V3 is not zero.
While this is very true, it relies on a fairly subtle understanding of how currents in ideal voltage sources interact. There are a couple (probably more) reasonable ways to explain it. Because an ideal voltage source maintains its terminal voltage independent of how much current is flowing in the source, different mesh currents within a voltage source don't interact. You can drive this point home by duplicating the source in parallel, moving them apart, arguing that there is no need for any current to flow in the bridging wire (though this argument itself has some subtle issues since, in actuality, the current flowing in that wire is completely undefined) and then cut the wire to illustrate the isolating effect of an ideal voltage source in that situation.OK, but suppose the current in V3 is a different mesh current. Then the two mesh currents, I1 & I2, only overlap in the V1 source, making this a particularly easy problem to solve. There is no need to even write the mesh equations.
Homework Help is not Homework done for you. Solving it for them is setting them up for failure later.Peeps, since you are not going to solve this problem for OP, why are you wasting their time?
Wasting time? Not if someone (like me) can learn something simply by following this thread. To be perfectly honest, I don't recall ever hearing about a "Mesh" equation. Now I know there's something I need to look up and learn. That way when someone else asks a similar question instead of opening my mouth and looking foolish I can speak from a base of knowledge. Sometimes the best way to learn something is to teach it to others. They say "Practice makes perfect." Well, if I figure this thing out then I can practice by helping others learn something as well.Peeps, since you are not going to solve this problem for OP, why are you wasting their time?
Its all a bit confusing as there seems so many ways to solve the problem, but for all of them I run into problems. Using just KCL and KVL I came up with these equations:Wasting time? Not if someone (like me) can learn something simply by following this thread. To be perfectly honest, I don't recall ever hearing about a "Mesh" equation. Now I know there's something I need to look up and learn. That way when someone else asks a similar question instead of opening my mouth and looking foolish I can speak from a base of knowledge. Sometimes the best way to learn something is to teach it to others. They say "Practice makes perfect." Well, if I figure this thing out then I can practice by helping others learn something as well.
I'd like to hear the thread starters comments on all this. If it's helping them or exasperating them. Sometimes I ask for help and only find more exasperation. With persistence comes clarity. And with clarity comes ability. I am, if nothing else, persistent. I'll stick to it until it's firmly glued down.
Sorry mate, none of them make sense.Its all a bit confusing as there seems so many ways to solve the problem, but for all of them I run into problems. Using just KCL and KVL I came up with these equations:
IV1 = IR1 - IR2
IV1 = IR3 - IR4
> IR1 - IR2 = IR3 - IR4
R1(IR1) - V1 + R3(IR3) - V2 = 0
R2(RI2) - V3 + R4(IR4) + V1 = 0
However, there are not enough equations to solve for the variables so I guess I need another equation. I am unsure as to what this could be unless there is something I overlooked? I reckoned I would solve for the various currents and then use that to calculate V4.
Not true. I think you have too many names for the same variable. Try looking at where the same current flows through several components, then give that current a single name. Now try writing the KVL equations again. I'll bet you have enough equations to solve for the variables. My suggestion for the named currents is here:However, there are not enough equations to solve for the variables so I guess I need another equation.
by Jake Hertz
by Jake Hertz
by Aaron Carman