Calculate the energy of the Photon

Thread Starter

Mojo Pin__

Joined Apr 13, 2019
19
devices snip.PNG In the attached image I am having trouble understanding why for the 2nd transition it is

13.6 (1/ 3^2) eV.....

instead of

13.6 (1-(1/ 3^2)) eV.....

can someone help me understand please?
 

AlbertHall

Joined Jun 4, 2014
8,506
For the n=1 to n=3 transition the photon must supply the difference in energy between the two levels.
For the second case the final energy is just the kinetic energy as the electron is not part of the atom.
 

Thread Starter

Mojo Pin__

Joined Apr 13, 2019
19
For the n=1 to n=3 transition the photon must supply the difference in energy between the two levels.
For the second case the final energy is just the kinetic energy as the electron is not part of the atom.

Hi! Thanks for the response :) when trying to find the answer I thought it might be something to do with the image i posted below.

For transition 2 I thought that because the electron starts at energy level 3 and then is ejected there is only:

1/nlow^2

because there is no higher energy level I ignore the:

-1/nhigh^2

but include kinetic energy to calculate the energy of photon 2.

Do you think this would be an acceptable way of thinking about it?

Cheers!


Capture devices allaboutcircuits.PNG
 
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