Bussed Resistor Array Clarifiction

Thread Starter

jpcrowd

Joined Mar 1, 2022
10
I have a Bourns 4820P-2-103LF drawn up like this. Each Resistor is 10k Ohm. I am trying to read the resistance across the copper pads.
1648581588060.png1648581748647.png

Questions:
Is this drawn up in series?
If I measured resistance across this would it read 1/190k Ohm?
Is this readable on a voltmeter?
If a solder joint broke, would it then read 1/180k, then 1/170k, etc. (Assuming node 20 did not break).
 

sagor

Joined Mar 10, 2019
912
The way I see it, all the resistors are in parallel. So, final resistance would be 10k/#pins active = final ohms.
So, if the 20 pin device has 19 resistors, resistance will be 10k/19 = 526 ohms

(Diagram shows the 4816P-2 16 pin device, not 20 pin - typical example of BUSS design/layout)
 

Thread Starter

jpcrowd

Joined Mar 1, 2022
10
Oops, meant to write parallel. Thanks for the clarification though.

667 ohms (10k ohms/15)
I have the 20 pin model selected. The Bourns spec sheet only showed the 16 pin model so that's what I grabbed.
So then it would read 10k ohms / 19 = 526 ohm

On the resistance setting.
I should have clarified a bit more. This resistance isn't too small for a typically multimeter to read is it? Not sure how sensitive they usually are. Just this one I screen grabbed off amazon looks like it is sensitive down to the 100s and can read up to the 100Ms. So 10k/19=526 and 10k/1=10k should be totally readable. Just wanted to confirm.
multimeter.jpg
 

Thread Starter

jpcrowd

Joined Mar 1, 2022
10
The way I see it, all the resistors are in parallel. So, final resistance would be 10k/#pins active = final ohms.
So, if the 20 pin device has 19 resistors, resistance will be 10k/19 = 526 ohms

(Diagram shows the 4816P-2 16 pin device, not 20 pin - typical example of BUSS design/layout)
Thank you. Meant to right parallel. IDK why my brain switched those.
 
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