If I had a Pulsed DC Source, (E.G a battery that as soon as it was turned on we're to pulse positive current seeking ground.)

Could a boost or buck boost type converter be created without the switch to ground that's in between the inductor and diode?

 

If I had a Pulsed DC Source, (E.G a battery that as soon as it was turned on we're to pulse positive current seeking ground.)

Could a boost or buck boost type converter be created without the switch to ground that's in between the inductor and diode?

No. For a boost converter, the switch provides a conduction path from the output capacitor through the diode to the load. The path back to the DC source is through the inductor.

I'll have to get back to you on the buck-boost, but I think the answer is the same.
ETA: I was wrong on the buck-boost. If your source has a duty cycle control, then it should be possible to do that.

 

No. For a boost converter, the switch provides a conduction path from the output capacitor through the diode to the load. The path back to the DC source is through the inductor.

I'll have to get back to you on the buck-boost, but I think the answer is the same.
ETA: I was wrong on the buck-boost. If your source has a duty cycle control, then it should be possible to do that.

Thank you so much! It would need a duty control because if it was at 100 percent duty it would NOT be able to raise the voltage?

 

Thank you so much! It would need a duty control because if it was at 100 percent duty it would NOT be able to raise the voltage?

So, what do you imagine is the difference between building an actual buck-boost converter and one with an on/off DC source? In my mind there is not a great deal of difference.

 

So, what do you imagine is the difference between building an actual buck-boost converter and one with an on/off DC source? In my mind there is not a great deal of difference.

I needed only one direct path from positive to ground, without any of the positive signal reaching ground before the voltage was increased.

 

I needed only one direct path from positive to ground, without any of the positive signal reaching ground before the voltage was increased.

I don't understand what you mean. The point where the diode and the inductor come together needs to float. It should NEVER be connected to ground. Your duty cycled supply need to do the same thing. It must provide a voltage for some period of time and then it must go "high-impedance" for the remainder of the switching period.

 

I needed only one direct path from positive to ground, without any of the positive signal reaching ground before the voltage was increased.

Use piece of copper wire, which plated on one end by tallium-204 or strontium-90.
Then wire will charged positive, up to some kV (depends on wire holder isolation properties).

 

I don't understand what you mean. The point where the diode and the inductor come together needs to float. It should NEVER be connected to ground. Your duty cycled supply need to do the same thing. It must provide a voltage for some period of time and then it must go "high-impedance" for the remainder of the switching period.

What so you mean by "high impedance for the remaining of the switching period" ? Do you mean when the switch or pulsed suppy is in its "off" state?

 

What so you mean by "high impedance for the remaining of the switching period" ? Do you mean when the switch or pulsed suppy is in its "off" state?

In all switch mode power supplies, there are two distinct states. In the "ON" state, there is power supply that allows current to flow in an inductor. In the "OFF" state there must be a path, which does not include the power supply, for current to flow from the output capacitor through the load. Additionally, a power supply that is off does not behave like a switch.

Like this: