Boost Converter: Power Losses

Thread Starter

declan2693

Joined Feb 2, 2018
37
Hi,

I am trying to figure out the total losses of boost converter.

So my input is 2.9V and 100mA so that (2.9*100mA) = 0.29 Watts

My output is 5V and with 50 ohm resistor, 25/50 = 0.5W.

What am I missing as obviously there should be power losses not the other way around.

Circuit image -> boost.PNG
 

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artmaster547

Joined Jan 6, 2016
409
Hi,

I am trying to figure out the total losses of boost converter.

So my input is 2.9V and 100mA so that (2.9*100mA) = 0.29 Watts

My output is 5V and with 50 ohm resistor, 25/50 = 0.5W.

What am I missing as obviously there should be power losses not the other way around.

Circuit image -> boost.PNG
hmm this is weird does your converter deliver current to your load? Is there any way you could measure this the output power should definitely be equal or mostly likely less than the input
 

Thread Starter

declan2693

Joined Feb 2, 2018
37
hmm this is weird does your converter deliver current to your load? Is there any way you could measure this the output power should definitely be equal or mostly likely less than the input
As you can see from the image of the circuit, the amp meter reading from the load is -0.375ma to +0.080ma but the curcuit does work as intended.
 
Hi,

I am trying to figure out the total losses of boost converter.

So my input is 2.9V and 100mA so that (2.9*100mA) = 0.29 Watts

My output is 5V and with 50 ohm resistor, 25/50 = 0.5W.

What am I missing as obviously there should be power losses not the other way around.

Circuit image -> boost.PNG
I think boost converter IC does increase the current at certain output check the datasheet how much current it draws
 

kubeek

Joined Sep 20, 2005
5,730
As you can see from the image of the circuit, the amp meter reading from the load is -0.375ma to +0.080ma but the curcuit does work as intended.
The current is not continuous, therefore you cannot use some simple average or whatever to calculate the input power. You need to mulitply current times voltage for each point in time and then average that, there should be some way to do that in your simulator.
 

Thread Starter

declan2693

Joined Feb 2, 2018
37
The current is not continuous, therefore you cannot use some simple average or whatever to calculate the input power. You need to mulitply current times voltage for each point in time and then average that, there should be some way to do that in your simulator.
That worked thanks
 
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