steveb,
"Math models obscure the question as they simplify the concepts. Look to the full-blown details in order to understand how transistors actually work. As with any diode junction, the B-E junction contains an insulating "depletion layer" whose thickness is controlled by applied voltage. Make this insulating layer thicker, and the diode turns off (reverse biased), or make the layer thin enough, and charges are able to get across; the diode turns on. E.g. the diodes's current is controlled by the voltage applied to the diode's terminals. Now in a BJT there essentially are two currents in the same B-E diode junction: the base current and the Collector current, and... both are controlled by the thickness of the insulating B-E depletion layer. And the thickness of the B-E depletion layer is controlled by the applied voltage Vbe. THEREFORE, both the collector current Ic and the base current Ib are controlled by the Base-Emitter voltage Vbe. Things only SEEM confusing because Ib happens to be proportional to Ic. In reality Ib cannot affect Ic, instead both are affected by a third variable: the B-E voltage. Weird, eh? At the most fundamental level, BJTs and FETs are both controlled by voltage. However, in a BJT the main current must cross an insulating layer of variable thickness, while in an FET the main current remains in the conductive regions while the insulating regions encroach from the side. If a BJT acts like the dark lens in a pair of variable-density sunglasses, then an FET is more like a variable-aperature optical shutter or iris: a variable-sized empty hole. --Wjbeaty 21:29, Mar 20, 2005 (UTC) "
"It all boils down to whether we want to teach how transistors work, or whether we only want to solve some design equations. Never lose sight of the fact that the collector current is never directly controlled by the base current. If we drive the base with a constant current source, this creates a certain value of BE voltage. This BE voltage then determines the thickness of the depletion layer, which then controls the collector current. Yet if we could somehow hold Vbe constant while changing Ib, we'd find that Ib cannot control Ic. Be careful not to confuse the simplified "black box" mathematical model with the physics-based explanation of transistor behavior. Yes, simplified engineering equations say that Ic is determined by Ib, and these equations are incredibly useful... but these equations are "wrong" because they mislead us into believing that Ib directly affects Ic. It does not. Instead, Ib determies Vbe, and Vbe determines Ic, which shows that a transistor is a voltage-controlled device which pretends to be a current-controlled device. Many people seem to hate this fact, and try to talk themselves into believing that Ib directly affects Ic. But unfortunately there's no escaping the well-known transistor physics. If we want to know how transistors work, we have to confront the fact that the flow of Ib charges has no affect on the flow of Ic charges. Yet for simplified introductory classes where nobody cares how transistors actually work, it's fine to say that Ic is controlled by Ib... and then to never mention any complexities such as the fact that the control relies indirectly upon Vbe. On the other hand, if a more advanced textbook never mentions the Eber-Molls model, or worse, tries to use semiconductor physics concepts to "prove" that Ib affects Ic, then that author has a serious misconception, and is doing their readers a disservice. --Wjbeaty 20:02, 4 April 2006 (UTC)"
Ratch
Certainly, Ib does change because Vbe makes it change. Sedra and Smith shows that. Vbe also also makes Ic change too. Ib does not control Ic, but it is an indicator of what Ic is, because both Ic and Ib are controlled by a common parameter which is Vbe.Again, I don't understand your logic. You can't assume that only Vbe changes. If Vbe changes, then Ib changes too.
From a semiconductor physics point of view, Vbe controls Ic. Ib can be any value you want within the active region, but Vbe is really what is making Ic hold to its value. That does not mean that useful models and design cannot be made and done by taking advantage of the proportionality of Ib vs Ic. Sedra and Smith show no equation that relates Ic to Ib as it does Ic to Vbe.If I use a current source to drive a base emitter junction in a BJT, I force the development of Vbe on the diode section. The Vbe then forces the Ic to develop. OK, Vbe seems to be the physically important control from the physics point of view. So what? The total device has still been controlled by current.
The object of that reference was not to introduce new material, but to affirm what was already avered. It shows that I am not alone in my views, and that they are not some off the wall insight that was concocted just to cause controversy.Ok, I read through these. Yes, it is interesting but I see nothing new there.
The worker, the lowest person in the chain of command. He is the worker (Vbe) who directly affects what is going one. Notice the word "directly".Analogy: If the owner of a company orders his manager to tell a worker to do something, and the manager tells the worker to do that thing, and the worker then goes and does that thing, who is in control?
Thank you very much. I never came across that reference before. I can't imagine how I missed it. I am going to quote two paragraphs from it which summarize my views about this subject. Just disregard if you already assimilated this material.I'm not sure if this web-page has been referenced already, but I didn't see it. Again, I see the chicken and egg argument.
http://en.wikipedia.org/wiki/Talk:Bi...ion_transistor
"Math models obscure the question as they simplify the concepts. Look to the full-blown details in order to understand how transistors actually work. As with any diode junction, the B-E junction contains an insulating "depletion layer" whose thickness is controlled by applied voltage. Make this insulating layer thicker, and the diode turns off (reverse biased), or make the layer thin enough, and charges are able to get across; the diode turns on. E.g. the diodes's current is controlled by the voltage applied to the diode's terminals. Now in a BJT there essentially are two currents in the same B-E diode junction: the base current and the Collector current, and... both are controlled by the thickness of the insulating B-E depletion layer. And the thickness of the B-E depletion layer is controlled by the applied voltage Vbe. THEREFORE, both the collector current Ic and the base current Ib are controlled by the Base-Emitter voltage Vbe. Things only SEEM confusing because Ib happens to be proportional to Ic. In reality Ib cannot affect Ic, instead both are affected by a third variable: the B-E voltage. Weird, eh? At the most fundamental level, BJTs and FETs are both controlled by voltage. However, in a BJT the main current must cross an insulating layer of variable thickness, while in an FET the main current remains in the conductive regions while the insulating regions encroach from the side. If a BJT acts like the dark lens in a pair of variable-density sunglasses, then an FET is more like a variable-aperature optical shutter or iris: a variable-sized empty hole. --Wjbeaty 21:29, Mar 20, 2005 (UTC) "
"It all boils down to whether we want to teach how transistors work, or whether we only want to solve some design equations. Never lose sight of the fact that the collector current is never directly controlled by the base current. If we drive the base with a constant current source, this creates a certain value of BE voltage. This BE voltage then determines the thickness of the depletion layer, which then controls the collector current. Yet if we could somehow hold Vbe constant while changing Ib, we'd find that Ib cannot control Ic. Be careful not to confuse the simplified "black box" mathematical model with the physics-based explanation of transistor behavior. Yes, simplified engineering equations say that Ic is determined by Ib, and these equations are incredibly useful... but these equations are "wrong" because they mislead us into believing that Ib directly affects Ic. It does not. Instead, Ib determies Vbe, and Vbe determines Ic, which shows that a transistor is a voltage-controlled device which pretends to be a current-controlled device. Many people seem to hate this fact, and try to talk themselves into believing that Ib directly affects Ic. But unfortunately there's no escaping the well-known transistor physics. If we want to know how transistors work, we have to confront the fact that the flow of Ib charges has no affect on the flow of Ic charges. Yet for simplified introductory classes where nobody cares how transistors actually work, it's fine to say that Ic is controlled by Ib... and then to never mention any complexities such as the fact that the control relies indirectly upon Vbe. On the other hand, if a more advanced textbook never mentions the Eber-Molls model, or worse, tries to use semiconductor physics concepts to "prove" that Ib affects Ic, then that author has a serious misconception, and is doing their readers a disservice. --Wjbeaty 20:02, 4 April 2006 (UTC)"
Ratch