Hello,

I have a small project box with a 18650 cell connected to a TP4056 with protection circuit DW01A, and then two step up HW-183 in parallel, one stepping up to 7.5V powering an arduino and one stepping up to 5V powering a 5 neopixel strip ( WS2812B ) and a DF player.
It seemed the neopixel strip was drawing too much power so i removed it, and it was working fine for a week or so.

Now when switching on the power, it seems the TP4056 protection kicks in and shuts down the battery.
I was told it is because i used the 'OUT+' and 'OUT-' of my TP4056, whose protection circuit will probably be tripped by the current spikes from boost converter and DFplayer.

My question is : If i wire my loads (boost converters, arduino ect...) directly to the B+ and B- of the TP4056 instead of the OUT+ and OUT-, will the 18650 cell still be protected?

I attached the full schema of the TP4056 IC for more info.

Thanks!

 

No, wiring that way takes the protection board out if the circuit.

It might help to power both devices from one converter. I believe an Arduino board can be powered directly by 5V by bypassing its regulator. Boosting to 7.5V only to regulate it down to 5V with a linear regulator (as the Arduino does) is just wasteful, using nearly twice the battery power needed.