Your 1st opamp has a gain of 10k/1k= 10 so its output is 1V peak.
The 2nd opamp is not needed (the 1st opamp can easily have a gain of 50) and has a gain of 5 so its output is clipping at about 3.8V peak.
The 3rd opamp is not needed (the 1st opamp can have a gain of 50 and drive the output transistors) and has no voltage gain.
The output transistors might overload the 3rd opamp since some transistors have a high current gain and other transistors have a low current gain.
I think the output will be clipping at 1.5V to 3V peak when there is a 4.5 ohms load. The transistors are not biased so there will be awful crossover distortion.
Your simulation program is stupid because it doesn't know that the opamp output cannot go as high as the power supply voltage and that the output transistors also have a voltage loss because they are emitter-followers.
You could have the same results if you used 1 opamp, two resistors to set the gain and 2 transistors. A very, very simple circuit.
The 2nd opamp is not needed (the 1st opamp can easily have a gain of 50) and has a gain of 5 so its output is clipping at about 3.8V peak.
The 3rd opamp is not needed (the 1st opamp can have a gain of 50 and drive the output transistors) and has no voltage gain.
The output transistors might overload the 3rd opamp since some transistors have a high current gain and other transistors have a low current gain.
I think the output will be clipping at 1.5V to 3V peak when there is a 4.5 ohms load. The transistors are not biased so there will be awful crossover distortion.
Your simulation program is stupid because it doesn't know that the opamp output cannot go as high as the power supply voltage and that the output transistors also have a voltage loss because they are emitter-followers.
You could have the same results if you used 1 opamp, two resistors to set the gain and 2 transistors. A very, very simple circuit.