Take a clear box and wire it up using some colored christmas lights, the kinds that work on 110 VAC. Take two SPST switches, big enough for you to disassemble and insert SMD diodes into. One switch has the diode one way and the second switch has it the other way. I'll post a schematic shortly. Wire a single series wire from the point where it enters the clear box, going to the first of two light sockets. From the first light socket to the second, run an additional wire. From there, wire the second light socket to one of the two switches. Then on to the next. Then back out of the box. What it ends up looking like is two lights in series with two series switches. No light should light up unless both switches are on. And when both switches are on both lights should light up.
Finally, carefully work the base of the lights off of the bulbs. Inside the base, wire up two more diodes, one one way and the second the opposite way. Use two different colored lights for obvious reasons (obvious to come).
Each bulb works on 110 VAC. But with the diode in one only the current will flow when flowing against the diode. Each switch having a diode in them will also prevent the current from flowing in both directions. Let's assume you have a red and a green bulb and one switch with a red handle and the other with a green handle. Plug the rig in and turn on both switches. Immediately both lights come on. Turn off the red switch and the red bulb (if you wired it correctly) will go off but the green will stay on. Turn the green switch off and the red on and the green bulb goes out and the red bulb comes on.
Now: To PROVE you didn't hide any wires, swap the bulbs in the bases. Put the red bulb in the place of the green bulb and the green in the red. Again, actuate the switches. Even though you've swapped positions, when you turn the red switch is turned on the red bulb lights. Regardless of which base it's screwed into. The secret is all in the diodes. As promised, a schematic will be forthcoming. But those who look at the circuit will be perplexed to figure out how the red switch controls the red bulb regardless of which socket it's screwed into.
Finally, carefully work the base of the lights off of the bulbs. Inside the base, wire up two more diodes, one one way and the second the opposite way. Use two different colored lights for obvious reasons (obvious to come).
Each bulb works on 110 VAC. But with the diode in one only the current will flow when flowing against the diode. Each switch having a diode in them will also prevent the current from flowing in both directions. Let's assume you have a red and a green bulb and one switch with a red handle and the other with a green handle. Plug the rig in and turn on both switches. Immediately both lights come on. Turn off the red switch and the red bulb (if you wired it correctly) will go off but the green will stay on. Turn the green switch off and the red on and the green bulb goes out and the red bulb comes on.
Now: To PROVE you didn't hide any wires, swap the bulbs in the bases. Put the red bulb in the place of the green bulb and the green in the red. Again, actuate the switches. Even though you've swapped positions, when you turn the red switch is turned on the red bulb lights. Regardless of which base it's screwed into. The secret is all in the diodes. As promised, a schematic will be forthcoming. But those who look at the circuit will be perplexed to figure out how the red switch controls the red bulb regardless of which socket it's screwed into.