If this seems too easy, then just let it slide a while..
If you were to ride a bike around a quarter-mile track once at an average speed of 10mph, what must your average speed be during a second lap, to make your average speed over both laps equal to 20mph?

 

Triggernum5, check your PM for my answer. I don't want to give it away too soon.
Mark

 

Cool, thanks.

 

I was watching Stargate SG-1 DVDs last night. According to the plot lines, there were two of the worm-hole machines on Earth.

 

Actually, I don't think a stargate would do it, they said its cold few seconds en route once in the show.. And even if it did, it would be tough to say you did anything since the point of origin would also be the point of destination..

 

20=\(\frac{10+x}{2}\)
= (20*2)-10 = 30mph??

 

How long would that take?

 

If you travel half the distance with half the speed, can you still reach in time?

 

I dunno.. Perhaps if one knew a bit about tachyons.. So is anybody still stumped by this, or what?

 

Voltboy,

Discoveries are made by questioning answers.

20=
= (20*2)-10 = 30mph??

OK, Vboy, I am questioning your answer. It takes 1/40 of an hour to travel the first quarter mile. It takes 1/120 of an hour to travel the next quarter mile at 30 mph. That makes the total time of 1/30 of an hour. Dividing that time into the total distance of 1/2 mile gives a average speed of 50 mph. Was that a discovery?

triggernum5,

I believe everyone appreciates the impossible solution.

Ratch