Hi everyone,
I have a little design challenge here. I made a ramp oscillator with a 555. Simple enough.
A ramp oscillator is simple if you stick to the 2/3VCC and 1/3VCC treshold. Since I use a 5V VCC, it would simply oscillate between 1.66v and 3.33V. I use a constant current source to charge the capacitor C1.
The interesting part is to adjust that lower limit to something closer to 0V. Ideally I would fix that lower limit somewhere around 0.2V.
In order to do so, I used a simple diode D1 to tie the OUTPUT to the CONTROL input. Doing so, when the output drops to 0V, the input CONTROL voltage drops to the Vf of the diode, in my case somewhere around 0,4V. Now that the 2/3VCC point of the 3 resistor bridge is forced to the diode Vf, the lower voltage comparison should be 0.2V instead of 1.66v.
I realized this circuit and there is a interesting behaviour that I cannot explain. Maybe someone will be able.
The diode makes the Ramp signal back to zero! I would have expected the lower comparator to Set the toggle when the voltage of the capacitor gets lower than the Vf/2 but it doesn't. I am missing something here, maybe someone can explain.
The two waveform are as follow:
Picture 1, Yellow is OUTPUT3, Pink is CONT5, and Blue is THRES+TRIG+DISCH (the actual ramp signal in the dicharge portion)
Picture 2 is without the feedback diode (open circuit), Yellow is OUTPUT3, Blue is THRES+TRIG+DISCH (ramp)
I would have expected the Ramp to stop discharging once the BLUE ramp crossed the PINK diode control voltage feedback. But unfortunately it doesn't.
Thanks in advance for your help, any input will help shine the light on this.
JF

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I have a little design challenge here. I made a ramp oscillator with a 555. Simple enough.
A ramp oscillator is simple if you stick to the 2/3VCC and 1/3VCC treshold. Since I use a 5V VCC, it would simply oscillate between 1.66v and 3.33V. I use a constant current source to charge the capacitor C1.
The interesting part is to adjust that lower limit to something closer to 0V. Ideally I would fix that lower limit somewhere around 0.2V.
In order to do so, I used a simple diode D1 to tie the OUTPUT to the CONTROL input. Doing so, when the output drops to 0V, the input CONTROL voltage drops to the Vf of the diode, in my case somewhere around 0,4V. Now that the 2/3VCC point of the 3 resistor bridge is forced to the diode Vf, the lower voltage comparison should be 0.2V instead of 1.66v.
I realized this circuit and there is a interesting behaviour that I cannot explain. Maybe someone will be able.
The diode makes the Ramp signal back to zero! I would have expected the lower comparator to Set the toggle when the voltage of the capacitor gets lower than the Vf/2 but it doesn't. I am missing something here, maybe someone can explain.
The two waveform are as follow:
Picture 1, Yellow is OUTPUT3, Pink is CONT5, and Blue is THRES+TRIG+DISCH (the actual ramp signal in the dicharge portion)
Picture 2 is without the feedback diode (open circuit), Yellow is OUTPUT3, Blue is THRES+TRIG+DISCH (ramp)
I would have expected the Ramp to stop discharging once the BLUE ramp crossed the PINK diode control voltage feedback. But unfortunately it doesn't.
Thanks in advance for your help, any input will help shine the light on this.
JF


