ripple 5%, 1V DC filtered output voltage and 220Vrms with 60hz source

i then used Multism and made a bridge rectifier and used the formulas to know what amount of capacitance etc.. that i need to get my proff's specifications.

i used this example from floyd's book as a guideline..

https://i.imgur.com/xTmz6bt.png

heres what i did.

Vpeakprimary = 1.414(220) = 311.08V

then use 10:1 step-down transformer

Vpeaksecondary = 0.1(311.08) = 31.108

the unfiltered peak full-wave rectified voltage = 31.108V - 1.4V= 29.708 V

since i need 5% ripple factor and 1volt dc output i wanted to know how much is the capacitance that i need(C)

0.05 = {[ 1 / (120hz) (1000ohm) (C) ] (29.708) } /1 V

which gave me 4951uF.

i strapped those values in the bridge rectifier i made in multism and i'm getting 29.376V when i measured my load resistor, but i need 1 volt output..

heres a picutre of the circuit i made:

https://i.imgur.com/GHnL6vW.png

is the ripple formula from floyd wrong? or did i just commit a mistake.