AC Circuit SuperPosition

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Digit0001

Joined Mar 28, 2010
100
Hi
DSC00068.JPG
I am having trouble getting the answer for the second part which used the current source. I have used nodal analysis like the one below, but still my calculated answer is incorrect

where
-j2 => 0.2 F
10j => 10j

Vo/8 + V0/-j2 + V0/10j = 4

P.S
 

t_n_k

Joined Mar 6, 2009
5,455
What you are forgetting is that

Z_inductor=jωL

Z_capacitor=1/(jωC)

For C=0.2F at ω=10

Z_C=1/(j2)=-j0.5

For L=1H at ω=10

Z_L=j10

Therefore ...

1/(Z_C)=1/(-0.5j)=j2

1/(Z_L)=1/(10j)=-0.1j
 
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