Hi
Can anyone help me with basic 8086 programming. i need to display the offset address of an element in an array. For example address of arr[2], arr[6] etc...

Here is what i've tried but i got a bunch of "rubbish" on display. It compile fine with no error/warning.

data segment

arr db 12,45,34,3 ;examples

data ends

code segment
assume cs:code, ds:data
start :


MOV AH, 9
LEA DX, arr+1 ;display arr[1]???
INT 21H

MOV AH, 4CH
INT 21H


code ends
end start

 

INT 21h / AH=9 - output of a string at DS: DX.
String must be terminated by '$'.

example:
          
     org 100h
     mov dx, offset msg
     mov ah, 9
     int 21h
     ret

 msg db "hello world $"

 

i still dont get it
am i using the wrong interrupt? should i use ah = 02

 

You have to write a routine to convert the binary into a character format.

 

You have to write a routine to convert the binary into a character format.

Oh i see.. no wonder i got bunch of funny chars. just to clarify so my offset address is in binary form? or hexadecimal? to convert it to ASCII for display.

Thanks

 

Oh i see.. no wonder i got bunch of funny chars. just to clarify so my offset address is in binary form? or hexadecimal? to convert it to ASCII for display.

This is always a misunderstanding with someone not in the know.
Everything is always in binary. Hexadecimal is all smoke and mirrors.

As my other quote: There are only 10 types of people in this world, those who understand binary and those who don't.