8086 array offset address

Thread Starter

ecjohnny

Joined Jul 16, 2005
142
Hi
Can anyone help me with basic 8086 programming. i need to display the offset address of an element in an array. For example address of arr[2], arr[6] etc...

Here is what i've tried but i got a bunch of "rubbish" on display. It compile fine with no error/warning.

data segment

arr db 12,45,34,3 ;examples

data ends

code segment
assume cs:code, ds:data
start :


MOV AH, 9
LEA DX, arr+1 ;display arr[1]???
INT 21H

MOV AH, 4CH
INT 21H


code ends
end start
 

MrChips

Joined Oct 2, 2009
21,343
INT 21h / AH=9 - output of a string at DS: DX.
String must be terminated by '$'.
Rich (BB code):
example:
          
     org 100h
     mov dx, offset msg
     mov ah, 9
     int 21h
     ret

 msg db "hello world $"
 
Last edited:

Thread Starter

ecjohnny

Joined Jul 16, 2005
142
You have to write a routine to convert the binary into a character format.
Oh i see.. no wonder i got bunch of funny chars. just to clarify so my offset address is in binary form? or hexadecimal? to convert it to ASCII for display.

Thanks
 

MrChips

Joined Oct 2, 2009
21,343
Oh i see.. no wonder i got bunch of funny chars. just to clarify so my offset address is in binary form? or hexadecimal? to convert it to ASCII for display.
This is always a misunderstanding with someone not in the know.
Everything is always in binary. Hexadecimal is all smoke and mirrors.

As my other quote: There are only 10 types of people in this world, those who understand binary and those who don't.
 
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