ronsimpson
- Joined Oct 7, 2019
- 3,052
60 leds on a battery
- Thread starter alberttester
- Start date
https://www.amazon.com/EDGELEC-Diff...c+100pcs+5mm+red+lights&qid=1574259822&sr=8-1
this is the led I wont to use.
this is the led I wont to use.
Don't waste your money buying generic LEDs from Amazon. Buy from an electronics parts distributor (Mouser, Newark, Jameco) and get something that has a manufacturer part number and datasheet. Buy ultrabrights so you can operate them at low current.
This is what you care most about from your link:
DC 2.0V-2.2V (IF=20mA) / 0.06 Watts / 2pin / DIP LEDs
They will likely work fine with a forward voltage of 2.0 or 2.1 volts and a forward current of 10 to 15 mA. You can experiment a little. Using a 9 volt source and 2.1 volts at 15 mA it looks like this.
3 * 2.1 V = 6.3 V so 9.0 V - 6.3 V = 2.7 V / 0.015 Amp = 180 Ohms. Choose a series resistor of about 180 Ohms. You will have 20 strings of 3 LEDs per string and each string draws about 0.015 Amp or a total current draw of about 300 mA. Using a standard 9.0 Volt battery is a poor choice as life will be short. You can try running your LEDs at 2.0 V and 10 mA and see if that is bright enough but even at that a 9.0 V battery will have a short life.
Ron
Audioguru again
- Joined Oct 21, 2019
- 6,710
Amazon sells cheap Chinese clothing, cheap Chinese shoes and cheap Chinese LEDs. Maybe the unknown LED manufacturer (EDGELEC in China) does not know how to make LEDs properly. When you buy cheap stuff then you usually get cheap stuff.
Subhash Nagaraj
- Joined Feb 26, 2016
- 3
Thank you for correcting me regarding the use of capacitors and Voltage and current limiting capability of LEDs.
But darlington pair amplifiers can be used as they provide a high current gain at low frequency AC or DC input. Alternatively current boosters can also be used. They are used in many power supplies for the same reason. You can have properly biased darlington pair amplifier in series between LED and battery.
If not please enlighten me on what stops you from using it.
But darlington pair amplifiers can be used as they provide a high current gain at low frequency AC or DC input. Alternatively current boosters can also be used. They are used in many power supplies for the same reason. You can have properly biased darlington pair amplifier in series between LED and battery.
If not please enlighten me on what stops you from using it.
Audioguru again
- Joined Oct 21, 2019
- 6,710
LEDs in parallel must have their forward voltages the same. You must test them and match them into similar groups.
A transistor, darlington, Mosfet or any kind of amplifier does not boost the current from the battery. These amplifiers simply pass or reduce the current from the battery. The current of the signal that turns on or off the amplifier is reduced by the amplifier.
You can boost the number of batteries instead. One little battery powering 60 LEDs is very overloaded. Ten little batteries, each powering 6 LEDs is better. 12 little batteries, each powering 5 LEDs is much better.
One big battery can power 60 LEDs well.
A transistor, darlington, Mosfet or any kind of amplifier does not boost the current from the battery. These amplifiers simply pass or reduce the current from the battery. The current of the signal that turns on or off the amplifier is reduced by the amplifier.
You can boost the number of batteries instead. One little battery powering 60 LEDs is very overloaded. Ten little batteries, each powering 6 LEDs is better. 12 little batteries, each powering 5 LEDs is much better.
One big battery can power 60 LEDs well.
